\(=\dfrac{3}{10}-\dfrac{4}{9}.\dfrac{3}{4}.\dfrac{6}{9}+1\\ =\dfrac{3}{10}-\dfrac{1}{3}.\dfrac{6}{9}+1\\ =\dfrac{3}{10}-\dfrac{2}{9}+1\\ =\dfrac{3.9-2.10+90}{90}\\ =\dfrac{97}{90}\)
\(=\dfrac{3}{10}+1-\dfrac{4}{9}\cdot\dfrac{3}{4}\cdot\dfrac{2}{3}=\dfrac{13}{10}-\dfrac{2}{9}=\dfrac{117-20}{90}=\dfrac{97}{90}\)
\(0,3-\dfrac{4}{9}:\dfrac{4}{3}.\dfrac{6}{9}+1\)
\(=\dfrac{3}{10}-\dfrac{4}{9}.\dfrac{3}{4}.\dfrac{2}{3}+\dfrac{10}{10}\)
\(=\dfrac{27}{90}-\dfrac{20}{90}+\dfrac{90}{90}\)
\(=\dfrac{97}{90}\)