a) \(7^3\)
b) \(0,6^2\) và \(\left(-0,6\right)^2\)
c) \(\left(-\frac23\right)^3\)
d) \(1,2^2\) và \(\left(-1,2\right)^2\)
a: \(343=7\cdot7\cdot7=7^3\)
b: \(0,36=0,6\cdot0,6=\left(-0,6\right)\cdot\left(-0,6\right)\)
Do đó: \(0,36=\left(0,6\right)^2=\left(-0,6\right)^2\)
c: \(-\frac{8}{27}=\left(-\frac23\right)\cdot\left(-\frac23\right)\cdot\left(-\frac23\right)=\left(-\frac23\right)^3\)
d: \(1,44=1,2\cdot1,2=\left(-1,2\right)\cdot\left(-1,2\right)=\left(1,2\right)^2=\left(-1,2\right)^2\)