Question

Answer 1

a: \(x-\dfrac{1}{5}=\dfrac{9}{5}\)

=>\(x=\dfrac{9}{5}+\dfrac{1}{5}=\dfrac{10}{5}=2\)

b: \(\left(2x-3\right)\cdot\dfrac{1}{2}=8\)

=>\(2x-3=8:\dfrac{1}{2}=8\cdot2=16\)

=>2x=3+16=19

=>\(x=\dfrac{19}{2}\)

c: \(\dfrac{5}{7}-\dfrac{2}{7}\left|x\right|=\dfrac{5}{14}\)

=>\(\dfrac{2}{7}\left|x\right|=\dfrac{5}{7}-\dfrac{5}{14}=\dfrac{5}{14}\)

=>\(\left|x\right|=\dfrac{5}{14}:\dfrac{2}{7}=\dfrac{5}{14}\cdot\dfrac{7}{2}=\dfrac{5}{4}\)

=>\(\left[{}\begin{matrix}x=\dfrac{5}{4}\\x=-\dfrac{5}{4}\end{matrix}\right.\)

d: \(\left(-\dfrac{1}{2}\right)^{x+2}=-\dfrac{1}{32}\)

=>\(\left(-\dfrac{1}{2}\right)^{x+2}=\left(-\dfrac{1}{2}\right)^5\)

=>x+2=5

=>x=5-2=3