\(\left(\dfrac{1}{2}x-x+\dfrac{2}{3}\right)\left(2x^2-4\right)=0\)
=>\(\left(-\dfrac{1}{2}x+\dfrac{2}{3}\right)\cdot\left(x^2-2\right)=0\)
=>\(\left[{}\begin{matrix}-\dfrac{1}{2}x+\dfrac{2}{3}=0\\x^2-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}-\dfrac{1}{2}x=-\dfrac{2}{3}\\x^2=2\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=\dfrac{2}{3}:\dfrac{1}{2}=\dfrac{4}{3}\\x=\pm\sqrt{2}\end{matrix}\right.\)
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