Question

Answer 1

\(\left\{\left[\left(\dfrac{1}{25}-0,6\right)^2:\dfrac{49}{125}\right].\dfrac{5}{6}\right\}-\left[\left(\dfrac{-1}{3}\right)+\dfrac{1}{2}\right]\)
\(=\left\{\left[\left(\dfrac{1}{25}-\dfrac{3}{5}\right)^2.\dfrac{125}{49}\right].\dfrac{5}{6}\right\}-\left[\dfrac{-2}{6}+\dfrac{3}{6}\right]\)
\(=\left\{\left[\left(\dfrac{1}{25}-\dfrac{15}{25}\right)^2.\dfrac{125}{49}\right].\dfrac{5}{6}\right\}-\dfrac{1}{6}\)
\(=\left\{\left[\left(\dfrac{-14}{25}\right)^2.\dfrac{125}{49}\right].\dfrac{5}{6}\right\}-\dfrac{1}{6}\)
\(=\left\{\left[\dfrac{196}{625}.\dfrac{125}{49}\right].\dfrac{5}{6}\right\}-\dfrac{1}{6}\)
\(=\left\{\dfrac{4}{5}.\dfrac{5}{6}\right\}-\dfrac{1}{6}\)
\(=\dfrac{4}{6}-\dfrac{1}{6}\)
\(=\dfrac{3}{6}=\dfrac{1}{2}\)