\(\dfrac{x}{2}=\dfrac{y}{3}=k\)
\(\Rightarrow\dfrac{x}{2}.\dfrac{y^2}{9}=\dfrac{xy^2}{2.9}=\dfrac{144}{18}=8=k^3\)
\(\Rightarrow k=2\)
\(\Rightarrow\left\{{}\begin{matrix}x=2.2=4\\y=3.2=6\end{matrix}\right.\)
Vậy \(\left(x;y\right)=\left(4;6\right)\)