Question

Answer 1

a: Ta có: \(\widehat{ACE}+\widehat{EAC}=90^0\)(ΔAEC vuông tại E)

\(\widehat{ABD}+\widehat{BAD}=90^0\)(ΔADB vuông tại D)

mà \(\widehat{EAC}=\widehat{BAD}\)

nên \(\widehat{ACE}=\widehat{ABD}\)

b: Xét tứ giác AEHD có \(\widehat{AEH}+\widehat{ADH}+\widehat{EAD}+\widehat{EHD}=360^0\)

=>\(\widehat{A}+\widehat{EHD}=360^0-90^0-90^0=180^0\)

=>\(\widehat{A};\widehat{EHD}\) là hai góc bù nhau