\(\Leftrightarrow f'\left(x\right)=3x^2-4\left(2m-1\right)x+2-m=0\) có 2 nghiệm dương pb
\(\Leftrightarrow\left\{{}\begin{matrix}\Delta'=\left(2m-1\right)^2-3\left(2-m\right)>0\\x_1+x_2=\dfrac{4\left(2m-1\right)}{3}>0\\x_1x_2=\dfrac{2-m}{3}>0\end{matrix}\right.\)
\(\Leftrightarrow\dfrac{5}{4}< m< 2\)