Question

Answer 1

c: \(C=\left|x-3\right|-\left|x+3\right|< =\left|x-3-x-3\right|=6\)

Dấu '=' xảy ra khi (x-3)(x+3)>=0

=>\(\left[{}\begin{matrix}x>=3\\x< =-3\end{matrix}\right.\)

a: \(\left|x-2\right|>=0\forall x\)

=>\(6\left|x-2\right|>=0\forall x\)

=>\(-6\left|x-2\right|< =0\forall x\)

=>\(A=-6\left|x-2\right|+8< =8\forall x\)

Dấu '=' xảy ra khi x-2=0

=>x=2

b: \(\left|x-1\right|>=0\forall x\)

=>\(2\left|x-1\right|>=0\forall x\)

=>\(2\left|x-1\right|+3>=3\forall x\)

=>\(B=\dfrac{1}{2\left|x-1\right|+3}< =\dfrac{1}{3}\forall x\)

Dấu '=' xảy ra khi x-1=0

=>x=1