Câu 1:
\(a)11,2\left(3\right)=\dfrac{337}{30}\)
\(b)6,\left(03\right)=\dfrac{199}{33}\)
\(c)-2,3\left(16\right)=-\dfrac{2293}{990}\)
Câu 2:
\(a)1,\left(6\right)+\left(\dfrac{-2}{7}\right)-\left(-1,2\right)\)
\(=\dfrac{5}{3}-\dfrac{2}{7}+\dfrac{6}{5}\)
\(=\dfrac{175}{105}-\dfrac{30}{105}+\dfrac{126}{105}\)
\(=\dfrac{271}{105}\)
\(b)0,1\left(6\right)+2,\left(3\right)\)
\(=\dfrac{1}{6}+\dfrac{7}{3}\)
\(=\dfrac{1}{6}+\dfrac{14}{6}\)
\(=\dfrac{15}{6}\)
\(c,\left(\dfrac{-11}{8}\right).6,\left(3\right)+6,\left(3\right).\left(\dfrac{-5}{8}\right)\)
\(=6,\left(3\right).\left(\dfrac{-11}{8}+\dfrac{-5}{8}\right)\)
\(=\dfrac{19}{3}.\dfrac{-16}{8}\)
\(=\dfrac{19}{3}.\left(-2\right)\)
\(=\dfrac{-38}{3}\)
Bài 2:
\(a,-4,15+4,91=0,76\approx1\)
\(b)9,\left(49\right):\left[-5,\left(09\right)\right]=-1,8\left(650793\right)\approx0\)
