ĐKXĐ: \(\left\{{}\begin{matrix}x>=0\\x\ne25\end{matrix}\right.\)
Để N nguyên thì \(9⋮\sqrt{x}-5\)
=>\(\sqrt{x}-5\in\left\{1;-1;3;-3;9;-9\right\}\)
=>\(\sqrt{x}\in\left\{6;4;8;2;14;-4\right\}\)
mà \(\sqrt{x}>=0\forall x\) thỏa mãn ĐKXĐ
nên \(\sqrt{x}\in\left\{6;4;8;2;14\right\}\)
=>\(x\in\left\{36;16;64;4;196\right\}\)