\(A=\left[6.\left(-\dfrac{1}{3}\right)^2-3.\left(-\dfrac{1}{3}\right)+1\right]:\left(-\dfrac{1}{3}-1\right)^2\)
\(A=\left[6.\dfrac{1}{9}+1+1\right]:\left(-\dfrac{4}{3}\right)^2\)
\(A=\left[\dfrac{2}{3}+2\right]:\dfrac{16}{9}\)
\(A=\dfrac{8}{3}.\dfrac{9}{16}=\dfrac{3}{2}\)