Bài 1:
a: Bốn cặp góc kề nhau là: \(\widehat{yOt};\widehat{tOm}\); \(\widehat{xOm};\widehat{mOy}\); \(\widehat{xOz};\widehat{xOm}\); \(\widehat{yOz};\widehat{yOt}\)
b: Ba cặp góc kề bù là: \(\widehat{yOt};\widehat{xOt}\); \(\widehat{xOm};\widehat{yOm}\); \(\widehat{xOz};\widehat{yOz}\)
c: Hai cặp góc đối đỉnh là:
\(\widehat{yOt};\widehat{xOz}\); \(\widehat{xOt};\widehat{yOz}\)
Bài 2:
Ta có: \(\widehat{bMc}+\widehat{bMa}=\widehat{aMc}\)(tia Mb nằm giữa hai tia Ma và Mc)
=>\(\dfrac{3}{2}\cdot\widehat{aMb}+\widehat{aMb}=90^0\)
=>\(\dfrac{5}{2}\cdot\widehat{aMb}=90^0\)
=>\(\widehat{aMb}=90^0:\dfrac{5}{2}=36^0\)
\(\widehat{bMc}=\dfrac{3}{2}\cdot36^0=54^0\)
