`c, 8^(x + 3) + 2^(3x) - 2^9 = 2^18`
`=> (2^3)^(x + 3) + 2^(3x) - 2^9 = 2^18`
`=> 2^(3x + 9) + 2^(3x) - 2^9 = 2^18`
`=> 3x + 9 + 3x -9 = 18`
`=> 6x = 18`
`=> x = 3`
Vậy: `x=3`
`d, (x-5)^2 = (1 - 3x)^2`
`=> (x-5)^2 - (1 - 3x)^2= 0`
`=> (x-5 - 1 + 3x)(x - 5 + 1 - 3x) = 0`
`=> (4x - 6)(-2x - 4)=0`
`=> [(4x - 6 = 0),(-2x - 4 = 0):}`
`=> [(4x = 6),(-2x = 4):}`
`=> [(x = 3/2),(x = -2):}`
Vậy: `x= 3/2 ; x=-2`
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