\(\dfrac{3-x}{2020}+\dfrac{2026-x}{2023}=\dfrac{x+2018}{2021}\)
=>\(-\dfrac{x-3}{2020}+\left(\dfrac{2026-x}{2023}-1\right)=\left(\dfrac{x+2018}{2021}-1\right)\)
=>\(-\dfrac{x-3}{2020}+\dfrac{3-x}{2023}=\dfrac{x-3}{2021}\)
=>\(\left(x-3\right)\left(-\dfrac{1}{2020}-\dfrac{1}{2023}-\dfrac{1}{2021}\right)=0\)
=>x-3=0
=>x=3