Câu 10: \(\dfrac{x^2-4x+3}{x-3}=\dfrac{\left(x-3\right)\left(x-1\right)}{x-3}=x-1\)
=>Chọn D
Câu 9: \(\dfrac{6x^4+3x^3+18x^2}{3x}=2x^3+x^2+6x\)
=>Chọn A
Câu 8: \(\dfrac{4x^4+6x^5+14x^7}{2x^3}=\dfrac{4x^4}{2x^3}+\dfrac{6x^5}{2x^3}+\dfrac{14x^7}{2x^3}=2x+3x^2+7x^4\)
=>Chọn D
Câu 7:
\(\dfrac{8x^6+16x^5-10x^4}{2x^4}=4x^2+8x-5\)
=>Chọn A
Câu 6: \(\dfrac{6x^4+4x^3+8x^2}{2x}=\dfrac{6x^4}{2x}+\dfrac{4x^3}{2x}+\dfrac{8x^2}{2x}=3x^3+2x^2+4x\)
=>Chọn D
Câu 5:
\(\dfrac{4x^5-6x^6+12x^9}{2x}=\dfrac{4x^5}{2x}-\dfrac{6x^6}{2x}+\dfrac{12x^9}{2x}=2x^4-3x^5+6x^8\)
=>Chọn B
Câu 4: \(\dfrac{x^3-x^2-5x+21}{x^2-4x+7}=\dfrac{x^3-4x^2+7x+3x^2-12x+21}{x^2-4x+7}\)
=x+3
=>Chọn B
Câu 3: \(\dfrac{x^4+3x^2-2x+1}{x^2-1}=\dfrac{x^4-x^2+4x^2-4-2x+5}{x^2-1}=x^2+4+\dfrac{-2x+5}{x^2-1}\)
=>Đa thức dư là -2x+5
=>Chọn B
Câu 2: \(\dfrac{3x^5-9x^6+12x^9}{3x}=\dfrac{3x^5}{3x}-\dfrac{9x^6}{3x}+\dfrac{12x^9}{3x}\)
\(=x^4-3x^5+4x^8\)
=>Chọn A
Câu 1: \(\dfrac{4x^4+16x^5-4x^7}{4x^3}=\dfrac{4x^4}{4x^3}+\dfrac{16x^5}{4x^3}-\dfrac{4x^7}{4x^3}\)
\(=x+4x^2-x^4\)
=>Chọn D
