Question

Answer 1

a: \(A=\dfrac{1,11+0,19-13\cdot2}{2,06+0,54}-\left(\dfrac{1}{2}+\dfrac{1}{4}\right):2\)

\(=\dfrac{1,3-26}{2,6}-\dfrac{3}{4}:2\)

\(=\dfrac{1}{2}-10-\dfrac{3}{8}=\dfrac{1}{8}-10=-\dfrac{79}{8}\)

\(B=\left(5\dfrac{7}{8}-2\dfrac{1}{4}-0,5\right):2\dfrac{23}{26}\)

\(=\left(5+\dfrac{7}{8}-2-\dfrac{1}{4}-\dfrac{1}{2}\right):\left(2+\dfrac{23}{26}\right)\)

\(=\left(3+\dfrac{1}{8}\right):\dfrac{75}{26}=\dfrac{25}{8}\cdot\dfrac{26}{75}=\dfrac{1}{3}\cdot\dfrac{13}{4}=\dfrac{13}{12}\)

b: A<x<B

=>\(-\dfrac{79}{8}< x< \dfrac{13}{12}\)

mà x nguyên

nên \(x\in\left\{-9;-8;...;0;1\right\}\)