Vì `x` // `y`
`=>`\(\widehat{DAB}+\widehat{ADC}=180^0\)(2 góc trong cùng phía)
`=>`\(80^0+\widehat{ADC}=180^0\)
`=>`\(\widehat{ADC}=100^0\)
Có :\(\widehat{tBx}=\widehat{ABC}=110^0\)(2 góc dối dỉnh)
Lại có :\(\widehat{tBx}=\widehat{BCy}=110^0\)( 2 góc dồng vị)
\(\widehat{BAz}=\widehat{ADC}=100^0\)(2 góc dồng vị)