\(\dfrac{2}{9}\cdot\left[-\dfrac{4}{45}:\left(\dfrac{1}{5}-\dfrac{2}{15}\right)+1\dfrac{2}{3}\right]-\left(-\dfrac{5}{27}\right)\)
\(=\dfrac{2}{9}\cdot\left[-\dfrac{4}{45}:\dfrac{3-2}{15}+\dfrac{5}{3}\right]+\dfrac{5}{27}\)
\(=\dfrac{2}{9}\cdot\left[-\dfrac{4}{45}\cdot\dfrac{15}{1}+\dfrac{5}{3}\right]+\dfrac{5}{27}\)
\(=\dfrac{2}{9}\left(-\dfrac{4}{3}+\dfrac{5}{3}\right)+\dfrac{5}{27}=\dfrac{2}{9\cdot3}+\dfrac{5}{27}=\dfrac{7}{27}\)