Question

Answer 1

\(\dfrac{7}{8}-\left|3-x\right|=\dfrac{3}{4}\)

\(\Rightarrow\left|3-x\right|=\dfrac{7}{8}-\dfrac{3}{4}\)

\(\Rightarrow\left|3-x\right|=\dfrac{1}{8}\)

\(\Rightarrow\left[{}\begin{matrix}3-x=\dfrac{1}{8}\\3-x=-\dfrac{1}{8}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{23}{8}\\x=\dfrac{25}{8}\end{matrix}\right.\)

Vậy: \(x\in\left\{\dfrac{23}{8};\dfrac{25}{8}\right\}\).