Question

Answer 1

b: \(\left|x+\dfrac{3}{4}\right|:\dfrac{2}{3}+\dfrac{1}{3}=0\)

=>\(\left|x+\dfrac{3}{4}\right|:\dfrac{2}{3}=-\dfrac{1}{3}\)

=>\(\left|x+\dfrac{3}{4}\right|=-\dfrac{1}{3}\cdot\dfrac{2}{3}=-\dfrac{2}{9}\)(vô lý)

Vậy: \(x\in\varnothing\)

c: \(\left(\dfrac{9}{25}\right)^x=\left(\dfrac{5}{3}\right)^{-1}\cdot\left(\dfrac{3}{5}\right)^5\)

=>\(\left(\dfrac{3}{5}\right)^{2x}=\left(\dfrac{3}{5}\right)\cdot\left(\dfrac{3}{5}\right)^5=\left(\dfrac{3}{5}\right)^6\)

=>2x=6

=>x=6/2=3

d: \(0,5^{x+1}+0,5^x=1,5\)

=>\(0,5^x\cdot0,5+0,5^x=1,5\)

=>\(0,5^x\left(0,5+1\right)=1,5\)

=>\(0,5^x=1\)

=>x=0