b: \(\dfrac{3}{4}+\dfrac{1}{4}x=-\dfrac{1}{2}\)
=>\(\dfrac{1}{4}x=-\dfrac{1}{2}-\dfrac{3}{4}=-\dfrac{5}{4}\)
=>\(x=-\dfrac{5}{4}:\dfrac{1}{4}=-5\)
c: \(\dfrac{2}{3}+x=-\dfrac{1}{12}\)
=>\(x=-\dfrac{1}{12}-\dfrac{2}{3}\)
=>\(x=-\dfrac{1}{12}-\dfrac{8}{12}=-\dfrac{9}{12}=-\dfrac{3}{4}\)