a: \(x+\dfrac{1}{6}=\dfrac{5}{12}\)
=>\(x=\dfrac{5}{12}-\dfrac{1}{6}\)
=>\(x=\dfrac{5}{12}-\dfrac{2}{12}=\dfrac{3}{12}=\dfrac{1}{4}\)
d: \(\dfrac{1}{5}+\dfrac{4}{5}\cdot x=\dfrac{3}{4}\)
=>\(\dfrac{4}{5}\cdot x=\dfrac{3}{4}-\dfrac{1}{5}=\dfrac{15-4}{20}=\dfrac{11}{20}\)
=>\(x=\dfrac{11}{20}:\dfrac{4}{5}=\dfrac{11}{20}\cdot\dfrac{5}{4}=\dfrac{55}{80}=\dfrac{11}{16}\)