a: \(2\cdot3^{x-1}-7=11\)
=>\(2\cdot3^{x-1}=18\)
=>\(3^{x-1}=9\)
=>x-1=2
=>x=3
b: \(\left(\dfrac{7}{2}x+1,4\right)\left(-1,5+3x\right)=0\)
=>\(\left[{}\begin{matrix}3,5x+1,4=0\\3x-1,5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3,5x=-1,4\\3x=1,5\end{matrix}\right.\)
=>x=-0,4 hoặc x=0,5