ABCD là hình chữ nhật
=>\(AB^2+AD^2=BD^2\)
=>\(BD^2=4a^2+5a^2=9a^2\)
=>BD=3a
\(\overrightarrow{BD}+\overrightarrow{DC}+\overrightarrow{AB}\)
\(=\overrightarrow{AB}+\overrightarrow{BC}=\overrightarrow{AC}\)
=>\(\left|\overrightarrow{BD}+\overrightarrow{DC}+\overrightarrow{AB}\right|=AC=BD=3a\)