\(a,\left|1\dfrac{2}{3}-5x\right|=0\left(x>0\right)\)
\(\Rightarrow1\dfrac{2}{3}-5x=0\)
\(\Rightarrow5x=1\dfrac{2}{3}\)
\(\Rightarrow5x=\dfrac{5}{3}\)
\(\Rightarrow x=\dfrac{5}{3}:5=\dfrac{1}{3}\)
\(---\)
\(b,\left|x-\dfrac{2}{5}\right|+\dfrac{3}{4}=\dfrac{11}{4}\)
\(\Rightarrow\left|x-\dfrac{2}{5}\right|=\dfrac{11}{4}-\dfrac{3}{4}\)
\(\Rightarrow\left|x-\dfrac{2}{5}\right|=2\)
\(\Rightarrow\left[{}\begin{matrix}x-\dfrac{2}{5}=2\\x-\dfrac{2}{5}=-2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{12}{5}\\x=-\dfrac{8}{5}\end{matrix}\right.\)
#\(Toru\)
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