Question

Answer 1

Ta có:

\(A+1+2+2^2+2^3+...+2^{2015}\)

\(\Rightarrow2A=2+2^2+2^3+...+2^{2016}\)

\(\Rightarrow2A-A=\left(2+2^2+...+2^{2016}\right)-\left(1+2+...+2^{2015}\right)\)

\(\Rightarrow A=\left(2-2\right)+\left(2^2-2^2\right)+...+\left(2^{2015}-2^{2015}\right)+\left(2^{2016}-1\right)\)

\(\Rightarrow A=2^{2016}-1\)

Mà: \(A=2^{2016}-1\)

\(\Rightarrow A+1=2^{2016}-1+1=2^{2016}\)

Dưới dạng lũy thừa của 8 là: 

\(A+1=2^{2016}=\left(2^3\right)^{672}=8^{672}\)

Chọn phương án thứ 2