a) \(B=-2xy^2+\dfrac{1}{3}x^3y-x-\dfrac{1}{3}x^3y+xy^2+4x\)
\(B=\left(-2xy^2+xy^2\right)+\left(\dfrac{1}{3}x^3y-\dfrac{1}{3}x^3y\right)-\left(x-4x\right)\)
\(B=-xy^2+3x\)
Bậc: \(1+2=3\)
b) Thay \(x=1,y=2\) vào B ta có:
\(-1\cdot2^2+3\cdot1=-1\)
Vậy: ...