Question

Answer 1

`i, 2/3 x +1/2 = 3/10-1/5`

`=> 2/3 x +1/2= 3/10-2/10`

`=>2/3 x +1/2=1/10`

`=> 2/3x=1/10-1/2`

`=>2/3x= 1/10-5/10`

`=>2/3 x=-4/10`

`=> x=-2/5 :2/3`

`=> x= -2/5 xx 3/2`

`=>x= -6/10`

`=> x=-3/5`

`j, 2/3 + 1/3: x=-1/2`

`=> 1/3 : x= -1/2-2/3`

`=> 1/3 : x= -3/6 -4/6`

`=>1/3 :x=-7/6`

`=>x=1/3 : (-7/6)`

`=>x=1/3 xx (-6/7)`

`=>x= -6/21`

`=>x= -2/7`

`k, 2^x+4.2^x=5`

`=> 2^x(1+4)=5`

`=>2^x . 5=5`

`=> 2^x =5:5`

`=>2^x=1`

`=> 2^x=2^0`

`=>x=0`

`l,(x+2)^5=2^(10)`

`=> (x+2)^5=(2^2)^5`

`=>x+2=4`

`=>x=4-2`

`=>x=2`

`m,200-(2x+6)=4^3`

`=>2x+6=200-64`

`=>2x+6=136`

`=>2x=136-6`

`=>2x=130`

`=>x=130:2`

`=>x= 65`

`n, (17x-25):8 +65=9^2`

`=>  (17x-25):8=81-65`

`=>  (17x-25):8=16`

`=>17x-25=16xx8`

`=>17x-25=128`

`=>17x=128+25`

`=>17x=153`

`=>x=153:17`

`=>x=9`

`#` `dao``dao`

Answer 2

\(i,\dfrac{2}{3}x+\dfrac{1}{2}=\dfrac{3}{10}-\dfrac{1}{5}\)

\(\dfrac{2}{3}x+\dfrac{1}{2}=\dfrac{3}{10}-\dfrac{2}{10}\)

\(\dfrac{2}{3}x+\dfrac{1}{2}=\dfrac{1}{10}\)

\(\dfrac{2}{3}x=\dfrac{1}{10}-\dfrac{1}{2}\)

\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{-5}{10}\)

\(\dfrac{2}{3}x=\dfrac{-2}{5}\)

\(x=\dfrac{-2}{5}:\dfrac{2}{3}\)

\(x=\dfrac{-2}{5}.\dfrac{3}{2}\)

x=\(\dfrac{-3}{5}\)

\(j,\dfrac{2}{3}+\dfrac{1}{3}:x=\dfrac{-1}{2}\)

\(\dfrac{1}{3}:x=\dfrac{-1}{2}-\dfrac{2}{3}\)

\(\dfrac{1}{3}:x=\dfrac{-3}{6}+\dfrac{-4}{6}\)

\(\dfrac{1}{3}:x=\dfrac{-7}{6}\)

\(x=\dfrac{1}{3}:\dfrac{-7}{6}\)

\(x=\dfrac{1}{3}.\dfrac{6}{-7}\)

\(x=\dfrac{2}{-7}\)

k, 2^x+4.2^x=5 

   2^x.1 +4.2^x=5

  2^x.(1+4)=5

  2^x . 5=5

  2^x=5:5

  2^x =1 

=>2^x =2⁰

=>x=0

l,(x+2)⁵ =2¹⁰

=>(x+2)⁵ =4⁵

=>x+2=4

    x=4-2

    x=2

m, 200 - (2x+6)= 4³

     200 - (2x+6)= 64

              2x+6=200-64

              2x+6= 136

               2x   =136-6

              2x=130

                 x=130:2 

                 x= 65

n,(17x-25):8+65=9²

  (17x-25):8+65=81

    (17x-25):8   =81-65

    (17x-25):8   =16

 17x-25=16.8

  17x-25=128

   17x=128+25

 17x=153

    x=153:17

 x=9