Theo đề ta có: \(\widehat{AOB}\) kề \(\widehat{AOC}\)
\(\Rightarrow\widehat{AOB}+\widehat{AOC}=\widehat{BOC}\)
Mà: \(\widehat{AOB}=\dfrac{1}{3}\widehat{AOC}\)
\(\Rightarrow\dfrac{1}{3}\widehat{AOC}+\widehat{AOC}=60^o\)
\(\Rightarrow\dfrac{4}{3}\widehat{AOC}=60^o\)
\(\Rightarrow\widehat{AOC}=\dfrac{60^o}{\dfrac{4}{3}}=45^o\)
\(\Rightarrow\widehat{AOB}=\dfrac{1}{3}\widehat{AOC}=\dfrac{1}{3}\cdot45^o=15^o\)
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