Question

Answer 1

Lời giải:

$(2x-1)^4=(2x-1)^6$

$\Leftrightarrow (2x-1)^6-(2x-1)^4=0$

$\Leftrightarrow (2x-1)^4[(2x-1)^2-1]=0$

$\Rightarrow (2x-1)^4=0$ hoặc $(2x-1)^2=1$

Nếu $(2x-1)^4=0\Rightarrow 2x-1=0\Rightarrow x=\frac{1}{2}$

Nếu $(2x-1)^2=1=(-1)^2=1^2$

$\Rightarrow 2x-1=1$ hoặc $2x-1=-1$

$\Rightarrow x=1$ hoặc $x=0$

Vậy........