a: \(A=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}\)
\(=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\cdot6}=\dfrac{-2}{6}=-\dfrac{1}{3}\)
b: \(B=\dfrac{\dfrac{1}{3}+\dfrac{1}{7}-\dfrac{1}{13}}{2\left(\dfrac{1}{3}+\dfrac{1}{7}-\dfrac{1}{13}\right)}=\dfrac{1}{2}\)