a, \(G=\dfrac{25}{f}=\dfrac{25}{12,5}=2x\)
b, Ta có: \(\dfrac{h}{h'}=\dfrac{d}{d'}\)
Theo đề bài: \(\dfrac{h}{5h'}=\dfrac{d}{d'}\Rightarrow d'=5d\)
c, Ta có: \(\dfrac{1}{f}=\dfrac{1}{d}-\dfrac{1}{d'}\Leftrightarrow\dfrac{1}{12,5}=\dfrac{1}{d}-\dfrac{1}{5d}\Leftrightarrow d=10cm\)
\(\Rightarrow dd'=d+d'=d+5d=6d=6\cdot10=60cm\)