\(a,\dfrac{3}{8}+\dfrac{1}{2}+1\\ =\dfrac{3}{8}+\dfrac{4}{8}+\dfrac{8}{8}\\ =\dfrac{7}{8}+\dfrac{8}{8}\\ =\dfrac{15}{8}\\ b,\dfrac{3}{4}+\dfrac{11}{15}+\left(-1\right)\\ =\dfrac{3}{4}+\dfrac{11}{15}-1\\ =\dfrac{45}{60}+\dfrac{44}{60}-\dfrac{60}{60}\\ =\dfrac{89}{60}-\dfrac{60}{60}\\ =\dfrac{29}{60}\\ c,\dfrac{3}{4}+\left(-\dfrac{1}{3}\right)-\left(-\dfrac{5}{18}\right)\\ =\dfrac{3}{4}-\dfrac{1}{3}+\dfrac{5}{18}\\ =\dfrac{9}{12}-\dfrac{4}{12}+\dfrac{5}{18}\\ =\dfrac{5}{12}+\dfrac{5}{18}\\ =\dfrac{15}{36}+\dfrac{10}{36}\\ =\dfrac{25}{36}\\ d,\dfrac{1}{3}-\dfrac{1}{-4}-\dfrac{1}{2}\\ =\dfrac{1}{3}-\left(-\dfrac{1}{4}\right)-\dfrac{1}{2}\\ =\dfrac{1}{3}+\dfrac{1}{4}-\dfrac{1}{2}\\ =\dfrac{4}{12}+\dfrac{3}{12}-\dfrac{6}{12}\\ =\dfrac{7}{12}-\dfrac{6}{12}=\dfrac{1}{12}\\\)
\(e,\dfrac{1}{2}+\left(-\dfrac{1}{3}\right)+\dfrac{1}{4}+\dfrac{1}{6}\\ =\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{1}{6}\\ =\dfrac{6}{12}-\dfrac{4}{12}+\dfrac{3}{12}+\dfrac{2}{12}\\ =\dfrac{2}{12}+\dfrac{5}{12}\\ =\dfrac{7}{12}\\ g,\dfrac{2}{3}+\left(-\dfrac{3}{4}\right)+\dfrac{5}{8}+\left(-\dfrac{1}{2}\right)\\ =\dfrac{2}{3}-\dfrac{3}{4}+\dfrac{5}{8}-\dfrac{1}{2}\\ =\dfrac{16}{24}-\dfrac{18}{24}+\dfrac{15}{24}-\dfrac{12}{24}\\ =-\dfrac{2}{24}+\dfrac{3}{24}\\ =\dfrac{1}{24}\)
a: =3/8+4/8+8/8=15/8
b: =45/60+44/60-60/60=29/60
c: \(=\dfrac{27}{36}-\dfrac{12}{36}+\dfrac{10}{36}=\dfrac{25}{36}\)
d: \(=\dfrac{1}{4}+\dfrac{1}{3}-\dfrac{1}{2}=\dfrac{3+4-6}{12}=\dfrac{1}{12}\)
e: \(=\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{4}=\dfrac{1}{4}+\dfrac{1}{3}=\dfrac{7}{12}\)
g: \(=\dfrac{16}{24}-\dfrac{18}{24}+\dfrac{15}{24}-\dfrac{12}{24}=\dfrac{1}{24}\)
