Thay \(x=4\) vào \(x+\dfrac{5}{2}>6\)
\(\)\(4+\dfrac{5}{2}=\dfrac{8}{2}+\dfrac{5}{2}=\dfrac{13}{2}=6,5>6\left(tm\right)\)
Chọn \(x=4\)
Vì \(\dfrac{5}{2}=2,5\) mà để \(x+\dfrac{5}{2}\) \(>6\) thì \(x+2,5>6\)
Ta Có: \(6-2,5=3,5\)
\(=>x\) \(=4\)
Nếu thay x = 3 => 3 + \(\dfrac{5}{2}=\)\(\dfrac{11}{2}=5,5< 6\)
Nếu thay x = 4 => 4 + \(\dfrac{5}{2}=\dfrac{13}{2}=6,5>6\)
Nếu thay x = 1 => 1 + \(\dfrac{5}{2}=\dfrac{7}{2}=3,5< 6\)
Nếu thay x = 2 => 2 + \(\dfrac{5}{2}=\dfrac{9}{2}=4,5< 6\)
Ta chọn x = 4