Question

Answer 1

e: \(=\dfrac{2^{10}\cdot3^9-2^9\cdot3^8}{2^{10}\cdot3^9}=\dfrac{2^9\cdot3^8\left(2\cdot3-1\right)}{2^{10}\cdot3^9}=\dfrac{1}{6}\cdot5=\dfrac{5}{6}\)

f: \(=\dfrac{5^3\cdot3^3+5^3\cdot3^2-5^3}{6^3\cdot3^3+6^3\cdot3^2-6^3}=\dfrac{5^3}{6^3}=\dfrac{125}{216}\)

g: \(=125+\dfrac{3}{5}-97-\dfrac{2}{3}+97+\dfrac{2}{5}-125-\dfrac{1}{3}=0\)

h: \(=\dfrac{7}{3}\left(-\dfrac{3}{4}+\dfrac{2}{5}+\dfrac{3}{5}-\dfrac{1}{4}\right)=0\)