Question

Answer 1

a)Điều chỉnh C nằm giữa biến trở.

CTM: \(\left(R_{AC}//Đ\right)nt\left(R_{CB}//R\right)\)

\(R_Đ=\dfrac{U^2_Đ}{P_Đ}=\dfrac{6^2}{6}=6\Omega;I_{Đđm}=\dfrac{P_Đ}{U_Đ}=\dfrac{6}{6}=1A\)

\(R_{AC+Đ}=\dfrac{R_{AC}\cdot R_Đ}{R_{AC}+R_Đ}=\dfrac{\dfrac{24}{2}\cdot6}{\dfrac{24}{2}+6}=4\Omega\)

\(R_{CB+R}=\dfrac{R_{CB}\cdot R}{R_{CB}+R}=\dfrac{\dfrac{24}{2}\cdot12}{\dfrac{24}{2}+12}=6\Omega\)

\(R_{tđ}=4+6=10\Omega\)

b)\(I_{AC+Đ}=I=\dfrac{U}{R_{tđ}}=\dfrac{12}{10}=1,2A\)

\(U_Đ=U_{AC+Đ}=1,2\cdot4=4,8V\)

\(I_Đ=\dfrac{U_Đ}{R_Đ}=\dfrac{4,8}{6}=0,8A< I_{Đđm}\)

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