Question

Answer 1

\(\sqrt{2x-1}-\dfrac{2}{3}=\dfrac{3}{4}\\ \Leftrightarrow\sqrt{2x-1}=\dfrac{17}{12}\\ \Leftrightarrow2x-1=\dfrac{289}{144}\\ \Leftrightarrow2x=\dfrac{433}{144}\\ \Leftrightarrow x=\dfrac{433}{288}\left(tm\right)\)

Answer 2

<=> \(\sqrt{2x-1}=\dfrac{17}{12}\)

<=> 2x - 1 = \(\dfrac{289}{144}\)

<=> 2x = \(\dfrac{433}{144}\)=> x = \(\dfrac{433}{288}\)