\(a,2\dfrac{1}{3}+2\dfrac{2}{3}:\dfrac{1}{5}=\dfrac{7}{3}+\dfrac{8}{3}:\dfrac{1}{5}=\dfrac{7}{3}+\dfrac{8}{3}\times5=\dfrac{7}{3}+\dfrac{40}{3}=\dfrac{47}{3}\)
\(b,\dfrac{6}{5}-\dfrac{1}{15}-\dfrac{7}{9}=\left(\dfrac{6}{5}-\dfrac{1}{15}\right)-\dfrac{7}{9}=\left(\dfrac{18}{15}-\dfrac{1}{15}\right)-\dfrac{7}{9}=\dfrac{17}{15}-\dfrac{7}{9}=\dfrac{153}{135}-\dfrac{105}{135}=\dfrac{48}{135}=\dfrac{16}{45}\)
\(a.\dfrac{7}{3}+\dfrac{8}{3}:\dfrac{1}{5}=\dfrac{7}{3}+\dfrac{40}{3}=\dfrac{47}{3}\)
\(b.\dfrac{17}{15}-\dfrac{7}{9}=\dfrac{48}{15}\)
a)
\(\dfrac{7}{3}+\dfrac{8}{3}:\dfrac{1}{5}=\dfrac{7}{3}+\dfrac{40}{3}=\dfrac{47}{3}\)
b)
\(=\dfrac{54}{45}-\dfrac{3}{45}-\dfrac{35}{45}=\dfrac{16}{45}\)
\(a,2\dfrac{1}{3}+2\dfrac{2}{3}:\dfrac{1}{5}=\dfrac{7}{3}+\dfrac{8}{3}:\dfrac{1}{5}=\dfrac{7}{3}+\dfrac{8}{3}\times\dfrac{5}{1}=\dfrac{7}{3}+\dfrac{40}{3}=\dfrac{47}{3}\)
\(b,\dfrac{6}{5}-\dfrac{1}{15}-\dfrac{7}{9}=\dfrac{18}{15}-\dfrac{1}{15}-\dfrac{7}{9}=\dfrac{17}{15}-\dfrac{7}{9}=\dfrac{51}{45}-\dfrac{35}{45}=\dfrac{16}{45}\)
4 và 5
