Question

Answer 1

\(=\left[-\dfrac{1}{3}\right]^2\cdot\dfrac{4}{11}+\dfrac{7}{11}\cdot\left[-\dfrac{1}{3}\right]^2\)

\(=\dfrac{1}{9}\cdot\left(\dfrac{4}{11}+\dfrac{7}{11}\right)=\dfrac{1}{9}\)