Question

Answer 1

\(2x^2-x=0\\ \Leftrightarrow x\left(2x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\2x-1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\2x=1\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{2}\end{matrix}\right.\)

Vậy pt có nghiệm là x=0 và x=1/2

Answer 2

\(x^4+x=0\)

\(<=>x(x^3+1)=0\)

\(<=>x(x^3+1^3)=0\)

\(<=>x(x+3)(x^2-x+1^2)=0\)

\(<=>x(x+3)(x-1)^2=0\)

\(<=>\) \(\left\{{}\begin{matrix}x=0\\x+3=0\\\left(x-1\right)^2\end{matrix}\right.\)

\(<=>\) \(\left\{{}\begin{matrix}x=0\\x=-3\\x=1\end{matrix}\right.\)