Lời giải:
$A=\frac{1}{5}+\frac{1}{5^2}+\frac{1}{5^3}+...+\frac{1}{5^{2022}}$
$5A=1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{2021}}$
$\Rightarrow 5A-A=1-\frac{1}{5^{2022}}$
$\Leftrightarrow 4A=1-\frac{1}{5^{2022}}<1$
$\Rightarrow A< \frac{1}{4}$ (đpcm)