đk x ≠ -1
\(M=\dfrac{2x-3}{x+1}\\=2-\dfrac{5}{x+1}\)
=> \(x+1\inƯ\left(5\right)\\ Ư\left(5\right)=\left\{1;-1;5;-5\right\}\)
=> \(\left\{{}\begin{matrix}x+1=1\\x+1=-1\\x+1=5\\x+1=-5\end{matrix}\right.=>\left\{{}\begin{matrix}x=0\\x=-2\\x=4\\x=-6\end{matrix}\right.\left(thoaman\right)\)