\(1\dfrac{1}{4}x+15\%x=\dfrac{7}{15}\\ \dfrac{5}{4}x+\dfrac{3}{20}x=\dfrac{7}{15}\\ \left(\dfrac{5}{4}+\dfrac{3}{20}\right)x=\dfrac{7}{15}\\ \dfrac{25+3}{20}x=\dfrac{7}{15}\\ \dfrac{7}{5}x=\dfrac{7}{15}\\ x=\dfrac{7}{15}:\dfrac{7}{5}\\ x=\dfrac{1}{3}=>C\)