c) \(\dfrac{6+3^2.2-6.3^2}{3^2+3.3^2-3^4}=\dfrac{3.2.1+3.2.3-3.2.3^2}{3^2.1+3^2.3-3^2.3^2}=\dfrac{3.2\left(1+3-3^2\right)}{3^2\left(1+3-3^2\right)}=\dfrac{2}{3}\)
d) \(\dfrac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}=\dfrac{5^{10}.7^3-\left(5^2\right)^5.\left(7^2\right)^2}{125^3.7^3+\left(5^3\right)^3.\left(7.2\right)^3}=\dfrac{5^{10}.7^3-5^{10}.7^4}{\left(5^3\right)^3.7^3+\left(5^3\right)^3.7^3.2^3}=\dfrac{5^{10}.7^3-5^{10}.7^3.7}{\left(5^3\right)^3.7^3+\left(5^3\right)^3.7^3.8}=\dfrac{5^{10}.7^3\left(1-7\right)}{\left(5^3\right)^3.7^3\left(1+8\right)}=\dfrac{5^{10}.7^3.\left(-6\right)}{5^9.7^3.9}=\dfrac{-10}{3}\)
