Question

Answer 1

`(3x-2/3)^3 = -8/27`

`(3x-2/3)^3 =(-2/3)^3`

`3x-2/3=-2/3`

`3x=-2/3+2/3`

`3x=0`

`x=0:3`

`x=0`

Vậy `x=0`

Answer 2

\(\left(3x-\dfrac{2}{3}\right)^3=-\dfrac{8}{27}\)

\(\Leftrightarrow\sqrt[3]{\left(3x-\dfrac{2}{3}\right)^3}=\sqrt[3]{-\dfrac{8}{27}}\)

\(\Leftrightarrow3x-\dfrac{2}{3}=-\dfrac{2}{3}\)

\(\Leftrightarrow3x=0\Leftrightarrow x=0\)

Vậy \(x=0\).