Question

Answer 1

\(\dfrac{1}{2}x+1-4x+1-\dfrac{1}{2}x=0\\ -4x+2=0\\ -4x=-2\\ x=\dfrac{1}{2}\)

Answer 2

Ta có: \(\dfrac{1}{2}\left(x+2\right)-4\left(x-\dfrac{1}{4}\right)=\dfrac{1}{2}x\Leftrightarrow\dfrac{1}{2}\left(x+2\right)-\dfrac{1}{2}.8\left(x-\dfrac{1}{4}\right)=\dfrac{1}{2}x\Leftrightarrow\dfrac{1}{2}\left(x+2-8x+2\right)=\dfrac{1}{2}x\Leftrightarrow-7x+4=x\Leftrightarrow4=8x\Leftrightarrow x=\dfrac{1}{2}\)Vậy x= \(\dfrac{1}{2}\)

Chúc e học tốt