Question

Answer 1

\(MCD:R1nt\left[\left(R2ntR3\right)//R4\right]\)

\(\Rightarrow R=R1+R234=4+\dfrac{\left(3+6\right)\cdot3}{3+6+3}=6,25\Omega\)

\(\Rightarrow U=IR=0,8\cdot6,25=5V\)

Ta có: \(I=I1=I234=0,8A\Rightarrow\left[{}\begin{matrix}U1=I1\cdot R1=0,8\cdot4=3,2V\\U234=U4=U23=U-U1=5-3,2=1,8V\end{matrix}\right.\)

\(\rightarrow I23=I2=I3=\dfrac{U23}{R23}=\dfrac{1,8}{3+6}=0,2A\Rightarrow\left[{}\begin{matrix}U2=I2\cdot R2=0,2\cdot3=0,6V\\U3=U23-U2=1,8-0,6=1,2V\end{matrix}\right.\)

Answer 2

Thiếu R4