a, \(\dfrac{4}{3}a^2bc-2a^2c-\dfrac{9}{2}a^2b+2a^2c+a^2b-a^2bc=\dfrac{1}{3}a^2bc-\dfrac{7}{2}a^2b\)
b, \(2ab-2bc^2+ab+\dfrac{1}{2}c^2b-4cb^2+2cb^2=3ab-\dfrac{3}{2}bc^2-2cb^2\)
c, \(2x-\dfrac{4}{3}mn^2+\dfrac{1}{5}mn^2-\dfrac{4}{3}mn^2=2x-\dfrac{37}{15}mn^2\)
d, \(\dfrac{6}{5}a^2bc-3a^2bc-\dfrac{1}{3}a^2bc+4=-\dfrac{32}{15}a^2bc+4\)
e, \(\dfrac{4}{9}a^2c^4-\dfrac{2}{5}ac^4+\dfrac{2}{3}ac^4-\dfrac{1}{4}ac^4=\dfrac{4}{9}a^2c^4+\dfrac{1}{60}ac^4\)
a.
1.
\(=\dfrac{4a^2bc}{3}-\dfrac{2a^2c}{1}-\dfrac{9a^2b}{2}+\dfrac{2a^2c}{1}+a^2b-a^2bc\)
\(=\dfrac{4}{3}a^2bc-2a^2c-9a^2b+2a^2c+a^2b-a^2bc\)
\(=\left(\dfrac{4}{3}a^2bc-a^2bc\right)-\left(2a^2c-2a^2c\right)-\left(9a^2b-a^2b\right)\)
\(=\dfrac{1}{3}a^2bc-8a^2b\)
các câu sau em làm tương tự nhé
