n: \(99^x=1\)
=>x=0
o: \(3^x=9\)
nên x=2
p: \(4^x=64\)
nên x=3
q: \(5\cdot2^x+14=94\)
\(\Leftrightarrow5\cdot2^x=80\)
\(\Leftrightarrow2^x=16\)
hay x=4
`99^x = 1`
`=> 99^x = 99^0`
`=> x=0`
_____________________________________
`3^x=9`
`=> 3^x=3^3`
`=> x=3`
_____________________________________
`4^x=64`
`=> 4^x = 4^3`
`=> x=3`
_____________________________________
5.2^x+14 = 94`
`=> 5.2^x = 94 - 14`
`=> 5.2^x = 80`
`=> 2^x = 80 : 5`
`=> 2^x = 16`
`=> 2^x = 2^4`
`= x=4`
_____________________________________
`81 : 9^(x-1)=9`
`=> 9^(x-1)= 81 : 9`
`=> 9^(x-1) = 9`
`=> 9^(x-1) = 9^1`
`=> x-1 = 1`
`=> x = 1 + 1`
`=> x=2`
_____________________________________
`x^4 = 16`
`=> x^4 = 2^4`
`=> x=2`
_____________________________________
2^x : 2^5 = 1`
`=> 2^x : 32 = 1`
`=> 2^x = 1 xx 32`
`=> 2^x = 32`
`=> 2^x = 2^5`
`=> x=5`
